(7x+2)^(2)+6(7x+2)=(27)=27

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Solution for (7x+2)^(2)+6(7x+2)=(27)=27 equation: 



(7x+2)^(2)+6(7x+2)=(27)=27

We move all terms to the left:

(7x+2)^(2)+6(7x+2)-((27))=0

determiningTheFunctionDomain
(7x+2)^2+6(7x+2)-27=0

We multiply parentheses

(7x+2)^2+42x+12-27=0

We add all the numbers together, and all the variables

42x+(7x+2)^2-15=0

We move all terms containing x to the left, all other terms to the right

42x+(7x+2)^2=15

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